For your next titration you weigh out an actual amount of 624.3 mg of your sample. Dissolving in water and then titrating with 0.1482 M NaOH produces the pH titration curve shown below:
1.)Based on the above curve, what volume of NaOH (mL) was used to reach the equivalence point ?
Enter a numeric answer only, to three significant figures
2.)How many mmol of NaOH were added to the 624.3 mg of weak acid sample in order to reach the equivalence point?
3.)How many mmol of weak acid are in the titrated sample ?
4.)The molar mass of a compound is calculated by adding up the molar mass of the individual elements. This can be done when you know the molecular formula of a compound.
The effective molar mass (EMM) is used in identifying an unknown compound. A sample of the unknown is weighed to find the mass. Then an analytical technique is used to find the number of moles contained in the sample. Here the method used is titration of the weighed sample with NaOH of a known molarity. Dividing the mass of the sample by the moles found from the titration gives the EMM.
What is the EMM of the 624.3 mg sample of unknown acid that was titrated?
5.)What volume of NaOH was added to reach the half-titration (or half-equivalence) ?
6.To two significant figures, what is the pKa of the unknown acid?
