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Part BA Solubility Equilibrium and Ku Equilibrium system: PbCl2 (s)Pb (a) 2 CI (a) Observations Step 4 Step 5 Step 6 Sten 7 Observations upon placing the test Step 9 SntD he Powo)o olution e Precipitate Observations upon addition of just 1.0 mL Total volume of HCI required for noticeable precipitation 1.0 Observations upon placing the test e tube with precipitate in hot water d ssalve tube wih precipitate ins precipitate Come back Volume of water added to just dissolve mL Step 9 PbCla precipitate mL Step 10 Total solution volume upon completion 13 Analysis .Why didn't any solid PbCl, form immediately upon addition of 1 mL of HCI (aq) in Step 4? What condition must be met by [Pb '] and [Cr] if solid PbClh is to form? . Consider your observation in hot water in Step 6: - In which direction did the equilibrium shift? - Did the value of Ksp get smaller or larger? - Is the dissolution of PbCl2 (s) exothermic or endothermic? Explain below.
Part BA Solubility Equilibrium and Ku Equilibrium system: PbCl2 (s)Pb (a) 2 CI (a) Observations Step 4 Step 5 Step 6 Sten 7 Observations upon placing the test Step 9 SntD he Powo)o olution e Precipitate Observations upon addition of just 1.0 mL Total volume of HCI required for noticeable precipitation 1.0 Observations upon placing the test e tube with precipitate in hot water d ssalve tube wih precipitate ins precipitate Come back Volume of water added to just dissolve mL Step 9 PbCla precipitate mL Step 10 Total solution volume upon completion 13 Analysis .Why didn't any solid PbCl, form immediately upon addition of 1 mL of HCI (aq) in Step 4? What condition must be met by [Pb '] and [Cr] if solid PbClh is to form? . Consider your observation in hot water in Step 6: - In which direction did the equilibrium shift? - Did the value of Ksp get smaller or larger? - Is the dissolution of PbCl2 (s) exothermic or endothermic? Explain below.
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Jean KeelingLv2
28 Mar 2019
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