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11 Nov 2019
A CHEM 112 student has 75.0 mL sample of an unknown monoprotic acid solution. He titrated it with 0.100 M NaOH and it required 22.12 mL of the NaOH solution to reach the equivalence point of the titration 6. A) What is the concentration of the unknown acid in the original 75.0 mL solution? B) The student monitored the pH throughout the titration, and after he had added only 15.0 mL of the NaOH solution, the measured pH was 6.39. What is the value of Ka for this "unknown" acid?
A CHEM 112 student has 75.0 mL sample of an unknown monoprotic acid solution. He titrated it with 0.100 M NaOH and it required 22.12 mL of the NaOH solution to reach the equivalence point of the titration 6. A) What is the concentration of the unknown acid in the original 75.0 mL solution? B) The student monitored the pH throughout the titration, and after he had added only 15.0 mL of the NaOH solution, the measured pH was 6.39. What is the value of Ka for this "unknown" acid?
Patrina SchowalterLv2
10 Jun 2019