Use the dilution formula to calculate the concentrations of iron(III) ions and SCN ions when 5.00 mL of 0.002M iron(III) nitrate is mixed with 4.00 mL of 0.002 M NaSCN and dilute nitric acid is added to bring the total volume of the solution to 20.0 mL [M Fe]- [M SCN-] = Put these calculated values into the table below as the initial concentrations of the reactants When these reactants come to equilibrium, the concentration of FeSCN2+ in the mixture is 1.5 x 10 M With that information, complete the equilibrium table Fe3* SCN- ê·¼ Initial Change _ Equilibrium Calculate the equilibrium constant using the equilibrium concentrations calculated in the table above.