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Which is the percent ionization of a solution which is 0.222 M HNO2(Ka= 4.50 x 10-4) and 0.278 M KNO2?

Answer

A. 0.02%

B. 0.162%

C. 1.55 %

D. 3.45 %


Which is theequivalence-point pH if 25.0 mL HCOOH (1.8 x 10-4) requires 29.80mL 0.3567 M NaOH to reach the equivalence point?

Answer

A. 2.06

B. 5.48

C. 8.52

D. 9.26

  1. Which process best accounts for the numerical value of theequivalence-point pH after the titration of formic acid, HCOOH withNaOH?

    Answer

    A. HCOO- (aq) + H2O (l) <--------> HCOOH (aq) + OH-(aq)

    B. HCOOH(aq) + H2O(l)<-------> -COOH(aq) + H3O+(aq)

    C. HCOOH (aq) + H3O+(aq) <--------> HCOOH2+(aq) + H2O(l)

    D. HCOOH(aq) + H2O(l)<-------> HCOOH2+(aq) + OH-(aq)

    Which volume of 0.234 M HCl must be added to 45.0 mL 0.432 MCH3NH2(Kb = 3.70 x 10-4)to reach a pH of 11.21?

    Answer

    A. 5.00 mL

    B. 11.6 mL

    C. 14.0 mL

    D. 83.0 mL

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Patrina Schowalter
Patrina SchowalterLv2
28 Sep 2019
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