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mauvegoose56Lv1
28 Sep 2019
the first reaction in glycolysis is the phosphorylation ofglucose:Pi+glucose gives glucose-6-phosphate.This isthermodynamically unfavourable process, with change of freeenergy=+1kj/mol.In a liver cell at 37 degree celius theconcentration of both phosphate and glucose are normally maintainedat about 5mM each.What would the equilibrium concentration ofglucose-6-phosphate be,according to the above data?
the first reaction in glycolysis is the phosphorylation ofglucose:Pi+glucose gives glucose-6-phosphate.This isthermodynamically unfavourable process, with change of freeenergy=+1kj/mol.In a liver cell at 37 degree celius theconcentration of both phosphate and glucose are normally maintainedat about 5mM each.What would the equilibrium concentration ofglucose-6-phosphate be,according to the above data?
23 Apr 2023
Reid WolffLv2
28 Sep 2019
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