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The Ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. In the first step of the Ostwald process, ammonia is reacted with oxygen gas to produce nitric oxide and water. What is the maximum mass of H2O that can be produced by combining 55.0 g of each reactant?

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Casey Durgan
Casey DurganLv2
28 Sep 2019

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Related questions


The Ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. In the first step of the Ostwald process, ammonia is reacted with oxygen gas to produce nitric oxide and water.

4NH3(g)+5O2(g)⟶4NO(g)+6H2O(g)

What is the maximum mass of H2O that can be produced by combining 21.6 g of each reactant?

STRATEGY:

Convert 21.6 g NH3 to moles, then find the corresponding amount of H2O.

Convert 21.6 g O2 to moles, then find the corresponding amount of H2O.

Identify the limiting reactant and calculate the mass of H2O produced.

Step 1: 21.6 g NH3 and excess O2 produce 1.90 mol H2O.

Step 2: 21.6 g O2 and excess NH3 produce 0.810 mol H2O.

Step 3: When 21.6 g NH3 and 21.6 g O2 are mixed, how many moles of H2O form?

(1) 1.90 + 0.810 mol H2O

(2) 0.810 mol H2O

(3) 1.90 mol H2O

Calculate the mass of H2O produced from the number of moles of H2O.

mass: [???] g H2O

The Oswald process is used commercially to produce nitruc acid, which is, in turn, used in many modern chemical processes, ammonia is reacted with oxygen gas to produce nitric oxide and water. What is th maximum mass of H2O that can produced by combining 52.2 g of each reactant? 4NH3(g) +5O2(g) --> 4NO(g) +6H2(g)

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