Question

<p>The question I have been strugglingwith:&#160;40.00&#160;<imgsrc="http://session.masteringchemistry.com/render?tex=%7B%5Crm+mL%7D"alt="{\rm mL}" align="middle" />&#160;of0.100&#160;<imgsrc="http://session.masteringchemistry.com/render?tex=M" alt="M"align="middle" />&#160;<imgsrc="http://session.masteringchemistry.com/render?tex=%5C%3B%7B%5Crm%7B+Na%7D%7D_2+%7B%5Crm%7BCO%7D%7D_3"alt="\;{\rm{ Na}}_2 {\rm{CO}}_3" align="middle" />&#160;istitrated with 0.100&#160;<imgsrc="http://session.masteringchemistry.com/render?tex=M%5C%3B%7B%5Crm+HCl%7D"alt="M\;{\rm HCl}" align="middle" />. Calculate the pH at thestart of the titration. Calculate the volume of HCL required toreach the equivalence point (I know it's 40 ml but I don't know howit fits in step by step). Then&#160;
<div class="partText">Calculate the predominant speciespresent at the first equivalence point.</div>
<div class="partInstructions">Express your answer as achemical formula. (<imgsrc="http://session.masteringchemistry.com/render?chemtex=%5Crm%7BHCO_%7B3%7D%7B%5E%7B-%7D%7D%7D"alt="\rm{HCO_{3}{^{-}}}" align="middle" />&#160;buthow?)&#160;
<div class="partText">Calculate the additional volumeof&#160;<imgsrc="http://session.masteringchemistry.com/render?tex=%7B%5Crm+HCl%7D"alt="{\rm HCl}" align="middle" />&#160;required to reach thesecond equivalence point.</div>
<div class="partInstructions">Express your answer using foursignificant figures.</div>
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<div class="answer"><spanclass="solveFor">&#160;&#160;<imgsrc="http://session.masteringchemistry.com/render?tex=V" alt="V"align="middle" />&#160;&#160;=</span><spanclass="solution"><span>40.00</span></span><spanclass="units">&#160;&#160;<imgsrc="http://session.masteringchemistry.com/render?tex=%5Crm+mL"alt="\rm mL" align="middle" /></span></div>
<span class="correct">Correct</span></div>
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<div id="part_id6007923" class="partVisible">PartE</div>
<div class="partText">Calculate the predominant speciespresent at the second equivalence point.</div>
<div class="partInstructions">Express your answer as achemical formula.</div>
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<div class="answer"><span class="solution"><imgsrc="http://session.masteringchemistry.com/render?chemtex=%5Crm%7BH_%7B2%7DCO_%7B3%7D%7D"alt="\rm{H_{2}CO_{3}}" align="middle"/></span></div>
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<div class="m"><spanclass="correct">Correct</span></div>
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<div class="m"><span class="correct">Calculatethe&#160;<imgsrc="http://session.masteringchemistry.com/render?tex=%7B%5Crm+pH%7D"alt="{\rm pH}" align="middle" />&#160;at the secondequivalence point.<br /></span></div>
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