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10. CISPLATIN (Pt(NH3)2CL2) IS A COMMON CHEMOTHERAPEUTIC AGENT AND IS PREPARED BY REACTING AMMONIA WITH POTASSIUM TETRACHLOROPLATINATE: K2PtCL4 + NH3 ----------> KCL + Pt(NH3)2CL2. HOW MANY GRAMS OF AMMONIA ARE NEEDE TO REACT WITH 50.0 GRAMS OF POTASSIUM TETRACHLOROPLATINATE? THEN CALCULATE HOW MANY GRAMS OF CISPLATIN ARE FORM FROM 50.0 GRAM OF POTASSIUM TETRACHLOROPLATINATE, IF THE YEILD FOR REACTION IS 75 PRECENT.

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Trinidad TremblayLv2
28 Sep 2019
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If this reaction produced 97.2 g of KCl, how much O2 was produced (in grams)?

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