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(1 point)
The figure shows how a function f(x) and its linear approximation (i.e., its tangent line) change value when
x changes from x0 to x0+dx.
Suppose f(x)=x2+4x, x0=2 and dx=0.04. Your answers below need to be very precise, so use many decimal places.
(a) Find the change Îf=f(x0+dx)âf(x0)).
Îf =
(b) Find the estimate (i.e., the differential) df=fâ²(x0)dx.
df =
(c) Find the approximation error |Îfâdf|
Error =
(Click on graph to enlarge)
y= f(x) f(da) ETro Tangent df = f' (x)dx f(ro) T0
(1 point)
The figure shows how a function f(x) and its linear approximation (i.e., its tangent line) change value when x changes from x0 to x0+dx. Suppose f(x)=x2+4x, x0=2 and dx=0.04. Your answers below need to be very precise, so use many decimal places. (a) Find the change Îf=f(x0+dx)âf(x0)). Îf = (b) Find the estimate (i.e., the differential) df=fâ²(x0)dx. df = (c) Find the approximation error |Îfâdf| Error = |
|
y= f(x) f(da) ETro Tangent df = f' (x)dx f(ro) T0
1
answer
0
watching
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Tod ThielLv2
13 Nov 2019