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13 Nov 2019
Find the surface area of the part of the plane 2x + 2y + z 6 that lies above the region in the xy-plane bounded by x2 + y2-4, the x-axis, and the y-axis, as shown in the figure. 6 2x+2y + z=6 (0, 2, 2) (0, 2, 0) (2, 0, 2) (2,0,0) 3 x2 + y2 = 4
Find the surface area of the part of the plane 2x + 2y + z 6 that lies above the region in the xy-plane bounded by x2 + y2-4, the x-axis, and the y-axis, as shown in the figure. 6 2x+2y + z=6 (0, 2, 2) (0, 2, 0) (2, 0, 2) (2,0,0) 3 x2 + y2 = 4
Reid WolffLv2
22 Apr 2019