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13 Nov 2019
3.20
(1 point) Given e cos(t) e sin(t)je k Find the derivative R' (t) and norm of the derivative. R' (t) = IIR' (t)ll = Then find the unit tangent vector T(t) and the principal unit normal vector N(t) T(t) N(t) =
3.20
(1 point) Given e cos(t) e sin(t)je k Find the derivative R' (t) and norm of the derivative. R' (t) = IIR' (t)ll = Then find the unit tangent vector T(t) and the principal unit normal vector N(t) T(t) N(t) =
Reid WolffLv2
8 Apr 2019