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13 Nov 2019

Vector Calculus (4th Edition)

Chapter 5.6, Problem 22E

How do you find the spherical coordinates for a cone with the equation z=2sqr((x^2)+(y^2))? And the top of the cone is a sphere with the equation x^2+y^2=25. How do you find the centriod? just z

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Jamar Ferry
Jamar FerryLv2
12 Jun 2019

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Related questions

Show transcribed image text

Solve in spherical coordinates for ∫ ∫ ∫ z dV bounded above by the sphere x^2+y^2+z^2=2 and below by the cone z = (x^2+y^2)^1/2 (in spherical coordinates this is phi = pi/4)

Use spherical coordinates to setup and evaluate a triple integral for the volume of the region that lies above the cone z = sqrt(x^2 + y^2) and below the sphere x^2 + y^2 + z^2 = z.

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