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13 Nov 2019
Number 3 please. The answer should be x+4y-18z+13=0
ses 1-4, find an equation for the plane tangent to the given parametrized In Exercises1 fad surface at the specified point. din 1, x = 2u, y = u2 + u, z =v2, at (0,1,1) 2.x=u2-U2, y = u + u, z = u2 +40, at (-1,12) 3. x = u2, y = u sin e", z-|u cos e", at (13,-2, 1)
Number 3 please. The answer should be x+4y-18z+13=0
ses 1-4, find an equation for the plane tangent to the given parametrized In Exercises1 fad surface at the specified point. din 1, x = 2u, y = u2 + u, z =v2, at (0,1,1) 2.x=u2-U2, y = u + u, z = u2 +40, at (-1,12) 3. x = u2, y = u sin e", z-|u cos e", at (13,-2, 1)
Elin HesselLv2
15 Apr 2019