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10 Nov 2019
(1pt)Let f(X) = 5 sin x/2 sin x + 4 cos x Then f?(x) = 5(sin^2(x)+cos^2(x)y(sinx+2cos(x))^2 The equation of the tangent line to y = 1(x) at x = 0 can be written in the form y = mx + b where m = 1.25 and b= .
(1pt)Let f(X) = 5 sin x/2 sin x + 4 cos x Then f?(x) = 5(sin^2(x)+cos^2(x)y(sinx+2cos(x))^2 The equation of the tangent line to y = 1(x) at x = 0 can be written in the form y = mx + b where m = 1.25 and b= .
Elin HesselLv2
10 Jan 2019