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Calculus
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10 Nov 2019
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csc8x cos x dx sin8x dx/cos x; u = sin x, du = cos x dx, n = 8 cos x dx/sin8x; u = cos x, du = sin x dx, n = -8 cos x dx/sin8x; u = sin x, du = cos x dx, n = -8 -cos x dx/sin8x; u = sin x, du = -cos x dx, n = -8
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rajendran
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1 ] dt dx in aju 17. dlscca]_ (soc utan ur, dx a[arctanâ)-1 rus 21. dx [sinh u] = (cosh u)", 4,tanh u]-(sech? uju, 27, sic Integration. Formulas du = u + C cos u du sin u + C 14. sec u tan u du secu+ C 16. 18. du mm=.arcsina+C "С ton Miffilin Company, Inc.
bronzehornet861
(1 point) Use part of the Fundamental Theorem of Calculus to find the derivative of 9x cos(u3) du cos(x) dy dx sin(x)cos((cosx)ng)-9cos(3x)ng
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