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9 Nov 2019
1) responses!!
A. One way: an integral finding the volume of a solid ofrevolution.
B. Two Ways: an integral finding the volume of a solidof revolution and a correctly set up doubleintegral.
C. Three Ways: an integral finding the volume of asolid of revolution, a correctly set up double integral, and acorrectly set up triple integral.
You with to find the volume of a sphere with radius r. In how many ways could you set up the problem? (Don't set up integrates) (Select best response) (responses are below! not in picture) Use polar coordinates to set u p the double integral F (x, y) dA for f (x, y) = e-(x2 + y2)/2 with R : x2 + y2 25 and x 0 (don't evaluate, set up only) Use Spherical coordinates to set up the triple integral to Find the volume of the solid inside the hemisphere rho = 6, 0 phi pi/2 and inside the cone phi = pi/4 (Don't evaluate) (Set up only)
1) responses!!
A. One way: an integral finding the volume of a solid ofrevolution.
B. Two Ways: an integral finding the volume of a solidof revolution and a correctly set up doubleintegral.
C. Three Ways: an integral finding the volume of asolid of revolution, a correctly set up double integral, and acorrectly set up triple integral.
You with to find the volume of a sphere with radius r. In how many ways could you set up the problem? (Don't set up integrates) (Select best response) (responses are below! not in picture) Use polar coordinates to set u p the double integral F (x, y) dA for f (x, y) = e-(x2 + y2)/2 with R : x2 + y2 25 and x 0 (don't evaluate, set up only) Use Spherical coordinates to set up the triple integral to Find the volume of the solid inside the hemisphere rho = 6, 0 phi pi/2 and inside the cone phi = pi/4 (Don't evaluate) (Set up only)
Irving HeathcoteLv2
26 Apr 2019