When an aircraft attempts to climb as rapidly as possible, itsclimb rate decreases with altitude. (This occurs because the air isless dense at higher altitudes.) The table shows performance datafor a single -engine aircraft.
altitude (1000 ft) 0 1 2 3 4 5 6 7 8 9 10
Climb Rate (ft/min) 925 875 830 780 730 685 635 585 535 490440
(b) If climb rate data were available in increments of 500ft, whatwould be the difference between a lower and upper estimate of climbtime based on 20 subdivisions?
"key concept: is the definite integral.", someone recommendedtrying...
Need help to do a simple dy/dx of the data with dy being thedifference between each of successive climb rates and dx being thedifference between your corresponding altitudes. This willgive the dependence of the planes climb rate based onaltitude, or slope of graph. take each of these slopes and halvethem, it will effectively give twice the resolution of climb ratedependence on altitude bc, and now have the dependence based on 20altitudes. Just multiply each of these new dy/dx's by each newaltitude(in increments of 500 now) and you will now have your climbrates based on 20 subdivisions of altitude. Use this to find yournew bounds.
Please explain and show your work, if you want lifesaverrating.
When an aircraft attempts to climb as rapidly as possible, itsclimb rate decreases with altitude. (This occurs because the air isless dense at higher altitudes.) The table shows performance datafor a single -engine aircraft.
altitude (1000 ft) 0 1 2 3 4 5 6 7 8 9 10
Climb Rate (ft/min) 925 875 830 780 730 685 635 585 535 490440
(b) If climb rate data were available in increments of 500ft, whatwould be the difference between a lower and upper estimate of climbtime based on 20 subdivisions?
"key concept: is the definite integral.", someone recommendedtrying...
Need help to do a simple dy/dx of the data with dy being thedifference between each of successive climb rates and dx being thedifference between your corresponding altitudes. This willgive the dependence of the planes climb rate based onaltitude, or slope of graph. take each of these slopes and halvethem, it will effectively give twice the resolution of climb ratedependence on altitude bc, and now have the dependence based on 20altitudes. Just multiply each of these new dy/dx's by each newaltitude(in increments of 500 now) and you will now have your climbrates based on 20 subdivisions of altitude. Use this to find yournew bounds.
Please explain and show your work, if you want lifesaverrating.
