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Consider the indefinite integral 6x3 + 5x2 + 4x + 3/x4 + 1x2 dx Then the integrand has partial fractions decomposition a/x2 + b/x + cx + d/x2 + 1 where a = b = c = d = Integrating term by term, we obtain that 6x3 + 5x2 + 4x + 3/x4 + 1x2 dx = +C Show transcribed image text Consider the indefinite integral 6x3 + 5x2 + 4x + 3/x4 + 1x2 dx Then the integrand has partial fractions decomposition a/x2 + b/x + cx + d/x2 + 1 where a = b = c = d = Integrating term by term, we obtain that 6x3 + 5x2 + 4x + 3/x4 + 1x2 dx = +C
Consider the indefinite integral 6x3 + 5x2 + 4x + 3/x4 + 1x2 dx Then the integrand has partial fractions decomposition a/x2 + b/x + cx + d/x2 + 1 where a = b = c = d = Integrating term by term, we obtain that 6x3 + 5x2 + 4x + 3/x4 + 1x2 dx = +C
Show transcribed image text Consider the indefinite integral 6x3 + 5x2 + 4x + 3/x4 + 1x2 dx Then the integrand has partial fractions decomposition a/x2 + b/x + cx + d/x2 + 1 where a = b = c = d = Integrating term by term, we obtain that 6x3 + 5x2 + 4x + 3/x4 + 1x2 dx = +C1
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Jarrod RobelLv2
5 Mar 2019