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12 Nov 2019
Row-Echelon Form In Exercises 19-24, whether the matrix is in row-echelon form it is whether it is also in reduced row-echelon form [1 0 0 0 1 0 0 1 0 0 2 0] [0 1 1 0 0 2 0 1] [2 0 0 0 -1 0 1 0 2 3 4 1] [1 0 0 0 1 0 2 3 1 1 4 0] [0 0 0 0 0 0 1 0 0 0 1 2 0 0 0] [1 0 0 0 0 0 0 0 0 0 1 0] System of Linear Equations In Exercises 25-38, solve the system using either Gaussian elimination with back-substitution or Gauss- Jordan x + 2y = 7 2x + y = 8 2x + 6y = 16 -2x - 6y = -16 -x + 2y = 1.5 2x - 4y = 3 2x - y = -0.1 3x + 2y = 1.6 -3x + 5y = -22 3x + 4y = 4 4x - 8y = 32 x + 2y = 0 x + y = 6 3x - 2y = 8
Row-Echelon Form In Exercises 19-24, whether the matrix is in row-echelon form it is whether it is also in reduced row-echelon form [1 0 0 0 1 0 0 1 0 0 2 0] [0 1 1 0 0 2 0 1] [2 0 0 0 -1 0 1 0 2 3 4 1] [1 0 0 0 1 0 2 3 1 1 4 0] [0 0 0 0 0 0 1 0 0 0 1 2 0 0 0] [1 0 0 0 0 0 0 0 0 0 1 0] System of Linear Equations In Exercises 25-38, solve the system using either Gaussian elimination with back-substitution or Gauss- Jordan x + 2y = 7 2x + y = 8 2x + 6y = 16 -2x - 6y = -16 -x + 2y = 1.5 2x - 4y = 3 2x - y = -0.1 3x + 2y = 1.6 -3x + 5y = -22 3x + 4y = 4 4x - 8y = 32 x + 2y = 0 x + y = 6 3x - 2y = 8
Jean KeelingLv2
21 Aug 2019