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10 Nov 2019
The polynomial f(x) = 2x^6 - 8x^5 + 10x^4 - 10x^2 + 8x - 2 has a stationary point at x = 1. This is because f^(1) (1) = Calculate the higher derivatives: f^(2) (1) f^(3) (1) f^(4) (1) f^(5) (1) So the smallest positive integer n > 1 for which f^(n) (1) notequalto 0 is n =
The polynomial f(x) = 2x^6 - 8x^5 + 10x^4 - 10x^2 + 8x - 2 has a stationary point at x = 1. This is because f^(1) (1) = Calculate the higher derivatives: f^(2) (1) f^(3) (1) f^(4) (1) f^(5) (1) So the smallest positive integer n > 1 for which f^(n) (1) notequalto 0 is n =
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Jamar FerryLv2
1 Oct 2019