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PHYS 103 Chapter : Lab Report Projectile Motion Assignment

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Elements of Physics Lab

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Behavioral and Individual Differences

<div class="c2">Vertical height h<sub>1</sub> = 5.00cm</div> <div class="c2"> h<sub>2</sub>=1.60cm</div> <div class="c2">d = 6.00cm<br> </div> <div class="c2"> To find the center ofmassspeed<em>v</em> on the plateau, we use the projectilemotion</div> <div class="c2"> equations.With<em>v</em><sub>o<em>y</em></sub> =0 (andusingâ<em>h</em>â for <em>h</em>2) Eq. 4-22givesthetime-offlight as</div> <div class="c2"> <em>t</em>=â2<em>h/g</em> </div> <div class="c2"> Then Eq. 4-21 (squared,andusing<em>d</em> for the horizontal displacement) gives</div> <div class="c2"> <em>v</em><sup>2</sup>=<em>gd</em><sup>2</sup>/2<em>h</em> Now, tofindthe speed <em>v</em>p at point<em>P</em>, we use energyconservationwith Eq. 11-5:</div> <h3 class="c3">Mechanical Energy on the Plateau =MechanicalEnergyat <em>P</em> </h3> <h3 class="c3">1/2 <em>mv</em><sup>2</sup>+1/2<em>I</em><sub>com</sub> Ï<sup>2</sup>+<em>mgh</em><sub>1</sub>=1/2<em>mv<sup>2</sup></em><sub>p</sub>+1/2<em>I</em><sub>com</sub>Ï<sup>2</sup><sub>p</sub> </h3> <div class="c2"> Using item (<em>f</em>) ofTable10-2,Eq. 11-2, and our expression(above)<em>v</em><sup>2</sup>=<em>gd</em><sup>2</sup>/2<em>h</em>,we<br> obtain</div> <p class="c5"><em> gd</em><sup>2</sup>/2<em>h</em>+10<em>gh</em><sub>1</sub>/7=<em>v</em><sub>p</sub><sup>2</sup></p> <div> which yields (using the values statedintheproblem) <em>v</em><sub>p</sub> = 1.34 m/s.</div>

PHYS 103 Chapter : Lab Report Projectile Motion Assignment

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Mechanical Energy on the Plateau =MechanicalEnergyat P

1/2 mv²+1/2I_com Ï²+mgh₁=1/2mv²_p+1/2I_comÏ²_p

PHYS 103 Chapter : Lab Report Projectile Motion Assignment

Get access

Related textbook solutions

Physics: Principles with Applications

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PHYS 103 Chapter Notes - Chapter 6: Ernest Webnje Nfor

PHYS 103 Chapter Notes - Chapter 5: Ernest Webnje Nfor, Centripetal Force, King James Version

PHYS 103 Chapter : Lab Report- Kinetics Assignment

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Mechanical Energy on the Plateau =MechanicalEnergyat P

1/2 mv2+1/2Icom Ï2+mgh1=1/2mv2p+1/2IcomÏ2p

1/2 mv²+1/2I_com Ï²+mgh₁=1/2mv²_p+1/2I_comÏ²_p