INDS 105 Lecture : Intro to INDS notes set 7

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victoriagabel1225

9 Nov 2022

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To document a space, stand in the room as you sketch it. Be sure to draw everything except the furniture. Once you have a good sketch, measure the room. Start in one corner and continue around until you end up where you started. Find the dimensions of all the walls; locate and measure all of the doors and windows. Measure anything else of importance, and write down these dimensions on your sketch. This drawing is what you will use to draft the space when you get back to your desk. After you get back to your workspace, lightly draft the plan manually or into a computer program. Drafted doors show the direction in which the door will move when opened or closed; this is called the door swing . Indicating door swing helps the designer and architect keep from adding abstructions to the door.

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Need detailed help/answers/advice.1. A picture framer has a piece of wood that measures one inch wide by 50 inches long. She would like to make a picture frame as shown below, and uses all 50 inches of wood she has. Notice that x and y in our sketch below are the outside dimensions of the frame. The picture looks like a rectangle with the measurements 1 inch around all sides and it says that the length of the rectangle is Y and the width is X. A. Write an equation that expresses the required relationship between variables x, y, and the total length of the wood. I got 2(x+y)=50 B. Solve your equation from part (A) for y in terms of x. Got y=25-x C. Write an expression (i.e. a function) that gives the interior area of the frame as a function of its exterior height x. x^2+25x-50?? Confused on everything from here on out. D. Find the values of x that make the interior area of the picture frame equal to zero. Explain why this is the case in the context of the picture frame problem. Draw the frames that correspond to these two extreme conditions. E. Use your function to find the inside dimensions that will make this area a maximum. State also the maximum internal area of the picture frame. The second part of it goes like this: Now the picture framer would like to rework this problem for a piece of wood of arbitrary length L. [In PART I, L was 50 inches. Now L becomes a new variable so that we can generalize what we did in PART I for a piece of wood of any arbitrary length, L] A. Write an equation that expresses the required relationship between variables x, y, and the total length of the wood L. In PART I, you had a linear equation of the form ax+by = 50 where a and b were numbers. Now you will have a slightly more complicated equation involving x, y and L, i.e. your equation will have three variables, x, y, and L in it. B. Solve your equation from part (A) for y in terms of x and L. C. Use your answer to part (B) to write an expression (i.e. a function) that gives the interior area of the frame as a function of its exterior height x, and the wood length L. [The variable y will not appear in this equation] D. Use your function to find the inside dimensions that will make this area a maximum. Now each of your inside dimensions will depend on L, i.e. they will be functions of L.

sangriasalmon464

Suppose that you are setting up a laboratory to study thedecision making behavior of rats. You will have them running a mazeand will put wires in their brains while they run it in order tomeasure what they are thinking as they make choices about where togo.

Suppose also that you want to be outside the room so as not todistract them while they are doing their tasks in case you need tointervene for some reason. You can think immediately think of twostraightforward approaches . (1) Put up a mirror in the room so youcan watch them while you are in the next room. (2) Put a webcam inthe room so you can watch them from anywhere.

There are various advantages and disadvantages to these choices,but you get distracted from making a decision by the followinginteresting question. In both cases, an image of the same volume ofspace containing the same objects is displayed on a two-dimensionalsurface â in one case the surface of the computer screen, in theother the surface of the mirror. Yet there is an interestingdifference. If you move away from looking at the center of thecomputer screen and go off to the side, the objects on the surfaceof the computer appear distorted â squashed along the horizontaldirection. (This is what it means to be a 2D image.) On the otherhand, if you walk off to the side of a mirror, nothing isdistorted. Everything looks normally 3D â you just see somewhatdifferent parts of the room.

Explain why this difference occurs in terms of the physics of lightand mirrors as you have learned them in class.

This is for an Alebra class, but it's more of engeneering Ithink.

Show how a 16" x 20" piece of cardboard can be used to create arange of open-topped boxes and give an analysis of your results. Besure to include a sketch of your box design (net), and to addressthe following:

Range of possible dimensions
Range of possible volumes
Characteristics of box of greatest efficiency

Your analysis should be thorough enough to easily reproduce yourresults. (Do everything to the nearest sixteenth of an inch)

INDS 105 Lecture : Intro to INDS notes set 7

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