CHE 131 : Exam Problem Sets #3
If
the
frequency
of
a
photon
of
red
light
is
twice
that
of
a
photon
of
infrared
radiation
,
how
much
more
energy
does
the
photon
of
red
light
have
energy
E.
hi
,
→
Frequency
↳
Planck
s
constant
(
6.
626×10-34
Js
)
Frequency
of
red
light
→
~
430
Hz
E.
hit
=
430
(
6.
626×10-3
"Js
)
=
2.8466×10-31
J
Frequency
of
infrared
radiation
→
-300
Hz
E.
hit
=
30016.626×10*3
"Js
)
=
I.
986×10-31
g-
Difference
:
2.8466×10-31
J
-
1.986×10-3
'
J
=
0.8606×10-3
'
J
