ENER Lecture Notes - Lecture 3: Net Force, University Of Florida, Verb
30 Jun 2021
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Question 1: a chain consisting of five links, each with mass 100 g, is lifted vertically with a constant acceleration of 2. 50 m/s2, as shown in below figure. Find, (a) the forces acting between adjacent links. (b) the force f exerted on the top link by the agent lifting the chain. (c) the net force on each link. Force acting on the object (f) is equal to the product of mas of the (m) and acceleration of the auto mobile (a). Weight of the automobile (w) is equal to the product of mass of the automobile (m) and acceleration due to gravity on the surface of the earth (g = 9. 81 m/s2). Solution: (a) the net force on each link is the same. To obtain the net force fnet on each link, substitute 0. 100 kg for m and 2. 50 m/s2 for a in the equation fnet = ma,
