CNST 4331 Lecture 5: Vertical Alignment examples
25 Jun 2021
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Vertical alignment: the tangent with two known points p and q, has the following known information: Point p has a stake value of 800 m and elevation of 103. 500 m: calculate the elevations along the tangent at exact 50 m multiples. K value for this particular road as 80, the chainage of the intersection (pi) is 680. 40 m: calculate the length of the curve; Vertical curve is to have equal tangents lengths, calculate: The length of the vertical curve is to have equal tangents lengths, calculate: chainages of the tangent points (bc & ec); and, the reduced levels along the tangent at exact 20 m multiples.
