University College - Chemistry Chem 112A Lecture 21: Thermal Entropy

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Fe(s): temp decreases ---heat transferred----> h2o: temp increases. Positional microstates don"t change because this heat transfer is completed at a constant volume in an isolated system. However the number of microstates must increase so as to not violate the second law of thermodynamics -> therefore there must be microstates associated with the energy of the system. S = qrev/t for an isothermal process ds = dqrev/t. Add up all the entropies: s = (cid:1516)(cid:3031)(cid:3044)(cid:3293)(cid:3280)(cid:3297)(cid:3021) S = (cid:1516)(cid:3031)(cid:3044)(cid:3293)(cid:3280)(cid:3297)(cid:3021) = (cid:1516) (cid:3041)(cid:3004)(cid:3271)(cid:3021) (cid:1856)(cid:1846) (cid:3021)(cid:3033)(cid:3021)(cid:3036) In any process, there will be a change in entropy that is associated with the change in volume (number of positional microstates) and with changing temperature (change in thermal microstates) Sh2o = 1000g/18g/mol * 74. 53 j/k*mol * ln(299/298) = 13. 87 j/k. Sfe = 56g/56g/mol * 25. 09 j/k*mol * ln(299/500) = -12. 9 j/k. =ncpln(tf/ti): this is for a constant pressure process with no phase changes, cp is independent of.

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