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L07 Chem 261 Lecture 18: Lecture 18

United States

Organic Chemistry I With Lab

University College - Chemistry

Ponder

Washington University in St. Louis

General  Chemistry I

Organic Chemistry III

General Biochemistry I

Calculus II

Calculus III

General Physics I

Solar System Astronomy

Introduction to Ecology

Principles of Biology I

General Chemistry  Laboratory  I

General Chemistry II

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Topics in Ancient Studies: Science and Medicine in Ancient Greece and Rome

Introduction to Archaeology

Ancient History: The Roman Republic

<p>The pH of household ammonia is 11; therefore, it molar hydrogen ion concentration</p> <table> <tbody> <tr> <td></td> <td>1.</td> <td> <p>1 x10<sup>11</sup> M</p> </td> </tr> <tr> <td></td> <td>2.</td> <td> <p>11 M</p> </td> </tr> <tr> <td></td> <td>3.</td> <td> <p>-11 M</p> </td> </tr> <tr> <td></td> <td>4.</td> <td> <p>1 x 10<sup>-11</sup> M</p> </td> </tr> </tbody> </table>

<p>Determine the K<sub>a</sub> forCH<sub>3</sub>NH<sub>3</sub><sup>+</sup> at 25<sup>0</sup>C. TheK<sub>b</sub> for CH<sub>3</sub>NH<sub>2</sub> is 4.4 X 10<sup>-4</sup>.</p> <p>Ka=</p> <table summary=""><tbody> <tr><td style="vertical-align:middle;"><p>K<sub>a</sub> = 2.3 X 10 <sup>-3</sup></p></td></tr> <tr> <td style="vertical-align:middle;white-space:nowrap;"></td> <td style="vertical-align:middle;"></td> </tr> </tbody></table> <p>K<sub>a</sub> = 3.1 X 10 <sup>-10</sup></p> <p>K<sub>a</sub> = 5.6 X 10 <sup>-10</sup></p> <p>K<sub>a</sub> = 2.3 X 10 <sup>-11</sup></p> <p>K<sub>a</sub> = 6.8 X 10 <sup>-11</sup></p>

L07 Chem 261 Lecture 18: Lecture 18

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Related Questions

	1.	1 x10¹¹ M
	2.	11 M
	3.	-11 M
	4.	1 x 10^-11 M

K_a = 2.3 X 10 ^-3