BIOL 540 Lecture Notes - Lecture 34: Xylulose, Sedoheptulose, Erythrose

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3 Jan 2020
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Stage 2 review start with 15 carbon atoms and rearrange them from. 3 five carbon molecules and still end up with 15. Carbon atoms but rearrange them so that there"s 2 six carbon molecules and 1 three carbon molecule of the three starting. 2 of them are molecules xylulose 5 phosphates and. 1 transketolase removes a two carbon section from xylulose 5 phosphate and add it the ribose 5 phosphate to the xylulose 5 phosphate then becomes. 3 phosphate gap a glyceraldehyde the ribose 5 phosphate becomes phosphate a sedoheptulose 7. 2 transaldolase removes a 3 carbon section from sedoheptulose. 7 phosphate and add it to the glyceraldehyde 3 phosphate glyceraldehyde 3 phosphate becomes fructose 6 phosphate first product of this pathway this is the sedoheptulose becomes erythrose 4 phosphate. 3 transketolase is used once again but this time remove a two carbon section from xylulose 5 phosphate to erythrose. Crythrose 4 phosphate becomes a fructose 6 phosphate.

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