STAT 1000Q Lecture Notes - Lecture 6: Sample Space

• School: UConn
• Department: Statistics
• Course: STAT 1000Q
• Professor: Robert Apruzese

Document Summary

Statistic notes 1000q- lecture #6- chapter 3 wrap up. Example 1: coin toss probabilities s= (hh, ht, th, tt), all outcomes equally likely. Finite samples w/ out equally likely outcomes. Formula: p(cid:894)bia(cid:895) = p(cid:894)a b(cid:895) / p(cid:894)a(cid:895) (good for any sample space not equal to 0) Example 1) an unfair die was tossed. P(cid:894)aic(cid:895): a c = (cid:894)(cid:1005), (cid:1009)(cid:895)= . (cid:1007)(cid:1009) To show independent, show these are true. Toss a coin once: s= (1, 2, 3, 4, 5, 6) A= (2, 4) and b= (4, 5, 6), show their independence. A b= {(cid:1008)} p(cid:894)aib(cid:895)= = p(cid:894)a(cid:895) which is (cid:1006)/(cid:1010) P(bia) = 1/2 = p(b) which is 3/6. The 80th percentile for math sat is 620 and 2 scores are randomly selected. A1= 1st person under 620, a2= 2nd person under 620. P(cid:894)both