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CHEM 1128Q Lecture Notes - Lecture 5: Iodine Clock Reaction, Reaction Rate, Rate Equation

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pearkoala574
1 Feb 2018
School
UConn
Department
Chemistry
Course
CHEM 1128Q
Professor
Clyde Cady

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CHEM 1128Q Full Course Notes
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CHEM 1128Q Full Course Notes
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Document Summary

K for different reactions have different units: the formula to figure out the units of k can be figured out by this table: Reaction rate can be recognized by looking at the graph: [m]/t (zero order) [a]0 [a] = kt: ln[m]/t (first order, ln[a0]/[a] = kt, 1/t (second order, 1/[a]-1/[a0] = kt. Rate information tables have information that is crucial to knowing the information for each rate law. 2h3o+ + h2o2 + 2i- 4h2o + i2. The rate is the same regardless of concentration and temperature. If not given a graph or an equation, reaction rate can still be determined by. 2: rate1/rate2 = ([a]1/[a]2)2, solve for m. A reaction has a [a] of 0. 2 m and a rate of 0. 288 m/min. The same reaction at [a] of 0. 170 m has a rate of 0. 245 m/min. M = 1: the reaction is first order.

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Related Questions

order inter. rate law graph slope

0 [A]=-kt+[A]_0 [A] vs t -k

1 ln[A]=-kt+ln[A]_0 ln[A] vs t-k

2 1/A=kt + 1/[A]_0 1/[A] vs t k

<?xml:namespace prefix = o ns ="urn:schemas-microsoft-com:office:office" /?> Using Integrated Rates Laws

The integrated rate laws for zero-,first-, and second-order reaction may be arranged such that theyresemble the equation for a straight line,.


A. The reactant concentration in a zero-order reaction was9.00

Order Integrated Rate Law Graph Slope 0 [A]=−kt+[A]0 [A] vs. t −k 1 ln[A]=−kt+ln[A]0 ln[A] vs. t −k 2 1[A]= kt+1[A]0 1[A] vs. t k The reactant concentration in a second-order reaction was 0.890 M after 190 s and 1.70×10−2 M after 705 s . What is the rate constant for this reaction?

Order Integrated Rate Law Graph Slope 0 [A]=−kt+[A]0 [A] vs. t −k 1 ln[A]=−kt+ln[A]0 ln[A] vs. t −k 2 1[A]= kt+1[A]0 1[A] vs. t k The reactant concentration in a first-order reaction was 9.50×10−2 M after 20.0 s and 6.20×10−3 M after 100 s . What is the rate constant for this reaction?