LIFESCI 4 Lecture Notes - Lecture 6: Chi-Squared Distribution, Centimorgan, Chi-Squared Test
3-Factor Test cCross
• assume parental generation is pure breed
• F1 crossed with pure breed
• + is doiat
• map distance between a & b? b & c?
- map distance between a & b: (42+9+38+11)÷1000 = 10 m.u.
- between b & c: (110+9+11+120)÷1000 = 25m.u.
- the largest # of phenotypes have parental class
• map distance between a & c?
- 10 + 25 = 35 m.u.
- OR:
Look for recombinants bt a & c (ignore b) => (42+110+38+120)÷1000 = 31m.u.
It’s saller tha 35 .u., because we are not counting double crossovers!
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