CHEM 001A Lecture Notes - Lecture 6: Barium Chloride, Solvation, Stoichiometry

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Chem 1a 10/19/17: solution concentrations, molarity (m) = mol/l, # mol = v*m , solution preparation, solution stoichiometry, the role of water as a solvent. Solutions: solutions are defined as homogeneous mixtures of two or more pure substances, the solvent is present in greatest abundance, all other substances are solutes, when water is the solvent, the solution is called aqueous solution. Molarity: molarity (m) = moles (n) of solute / volume (v) of solution in liters, m = n / v. If we know the volume (v) and the molarity (m) of a solution, we can calculate moles (n: n =v x m. Solvation: remember the rule: likes dissolve likes. 5 l x 0. 0525 m = . 02625 mol: al(no3)3 = 27. 0 g al + 3 (14. 0 g n) + 9 (16. 0 g o) = 213. 0 g/mol, 0. 2625 mol x 213. 0 g/mol = 5. 59 g.

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