MAT 21B Lecture Notes - Lecture 16: Specific Weight, Summation, Standard Deviation
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MAT 21B – Lecture 16 – Application of Definite Integrals in Moments
• Example: The first moment of the sequence x1 = 2, x2 = 5, x3 = 9 with weights
, respectively is: 2(7) + 5(3) + 9(1) = 38. This sum can
also be expressed with sigma notation such that
• The second moment from the example above is
• An application of first moments appears in the numerator of weighted averages.
Given the following table, the weighted average can be calculated.
Assignment
Score (%)
Weight on score (%)
Midterm #1
70
25
Quizzes
80
15
Let x1 = 70, , x2 = 80, and . Then the weighted average is
The numerator is the first moment.
• An application of the second moment appears in variance in standard deviation
• Problem: Another application of first moments appear in physics concept of
torque. Calculate the torque due to the wrench from following diagram:
The torque due to the person is The
wrench also has weight. Its linear weight density,
. The torque due to
the wrench, is where x is the length of the moment arm and
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Document Summary
Mat 21b lecture 16 application of definite integrals in moments: example: the first moment of the sequence x1 = 2, x2 = 5, x3 = 9 with weights. (cid:1875)(cid:2869)=(cid:889), (cid:1875)(cid:2870)=(cid:885), (cid:1875)(cid:2871)=(cid:883), respectively is: 2(7) + 5(3) + 9(1) = 38. Given the following table, the weighted average can be calculated. (cid:2871)(cid:2869) (cid:2871)(cid:2869) Let x1 = 70, (cid:1875)(cid:2869)=(cid:884)5, x2 = 80, and (cid:1875)(cid:2870)=(cid:883)5. The numerator (cid:1876)(cid:2869) (cid:1875)(cid:2869)+(cid:1876)(cid:2870) (cid:1875)(cid:2870) is the first moment. (cid:3051)(cid:3117) (cid:3050)(cid:3117)+(cid:3051)(cid:3118) (cid:3050)(cid:3118) (cid:2870)(cid:2873)+(cid:2869)(cid:2873: an application of the second moment appears in variance in standard deviation, problem: another application of first moments appear in physics concept of. Calculate the torque due to the wrench from following diagram: The torque due to the person is =(cid:883)5(cid:882) (cid:1864) (cid:883)(cid:882) (cid:1858)=(cid:883)5(cid:882)(cid:882) (cid:1858) (cid:1864). The torque due to the wrench, is = = (cid:1876) (cid:1875) where x is the length of the moment arm and dw is the weight of one rectangle (which was cut from vertical strips).