CHEM 132L Lecture Notes - Lecture 3: Colligative Properties, Molality, Melting Point
Name: Isbah Afzal
Lab Partner: Alexis Romas
CHEM-132-005
Due Date: 10/13/2017
Experiment #3 Freezing Point Report Requirements
Introduction:
Data Table 1:
Trial #1
Trial #2
Water
trial
Time (s)
Temperature (oC)
Time (s)
Temperature
(oC)
Time (s)
Temperature (oC)
20
14.3
20
13.0
20
18.0
30
12.2
30
10.3
30
14.8
40
9.8
40
7.9
40
11.9
50
7.7
50
6.0
50
9.6
60
6.0
60
4.5
60
7.7
70
4.3
70
3.2
70
6.3
80
2.0
80
2.0
80
5.0
90
1.8
90
1.0
90
3.7
100
0.6
100
0.0
100
2.7
110
-0.3
110
-0.8
110
1.7
120
-1.3
120
-1.6
120
0.9
130
-2.1
130
-2.5
130
0.2
140
-2.8
140
-3.7
140
0.2
150
-3.0
150
-4.3
150
0.2
160
-2.6
160
-4.7
160
0.2
170
-2.6
170
-3.3
170
0.1
180
-2.6
180
-2.7
180
0.1
190
-2.7
190
-2.6
190
0.1
200
-2.7
200
-2.7
200
0.1
210
-2.7
210
-2.7
210
0.1
220
-2.7
220
-2.7
220
0.1
230
-2.7
230
-2.7
230
0.1
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240
-2.8
240
-2.7
240
0.1
250
-2.8
250
-2.8
250
0.1
260
-2.8
260
-2.8
260
0.1
270
-2.8
270
-2.8
270
0.1
280
-2.8
280
-2.9
280
0.1
290
-2.9
290
-2.9
290
0.1
300
-3.0
300
-2.9
300
0.1
310
-3.0
310
-2.9
310
0.1
320
-3.0
320
-3.0
320
0.1
330
-3.0
330
-3.1
330
0.1
340
-3.0
340
-3.1
340
0.1
350
-3.0
350
-3.1
350
0.1
360
-3.1
360
-3.1
360
0.1
Data Table 2
Partner 1
Partner 2
Actual Mass
%
Molality, m
Corrected Tf
(oC)
Lizabeth Zepeda
Erica Gibbs
4.0
0.668866
-1.6
Elizabeth Fletcher
Paula Araneda
5.0
0.854329
-2.1
Max Smith
Konner Pavlik
6.0
1.021487
-2.3
Alexis Romas
Isbah Afzal
7.0
1.214446
-2.8
Vikram Sandhu
Dilveer Chahal
8.0
1.409387
-3.4
Cassandra Kelly
Amy Tien
9.0
1.59546
-3.0
John Whitehead
James Bryant
10.0
1.799043
-4.2
Graphs for Trial 1 &2 with hand-drawn freezing point:
-4
-3
-2
-1
0
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
050 100 150 200 250 300 350 400
Temperature
Time (s)
Trial 1
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Document Summary
Graphs for trial 1 &2 with hand-drawn freezing point: Trial 1 e r u t a r e p m e. Trial 2 e r u t a r e p m e. Graph of freezing point (tf) vs. mass % ethylene glycol freezing point (tf) vs. mass % ethylene glycol s s a. Show one sample calculation to find the mass % associated with -17. 80oc (use the trendline). Y = -2. 3647 (-17. 80) + 0. 4422 = 42. 53: show one sample calculation to find the tf for a 52. 0% mass solution (again, use the trendline). X = -21. 80 o c: for the 52. 0% mass solution, calculate the % error between this experimentally determined tf and the value reported by antifreeze manufacturers (tf = -36. 7 o c). % error = (experimental theoretical)/ theoretical x 100. = [-21. 80 o c (-36. 7 o c) / (-36. 7 o c] x 100. Graph plot tf vs. molality and fit a trendline to the class data.