CHE 110L Lecture 4: Determination of the Formula of a Metal Oxide

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The purpose of this lab was to prepare a metal oxide and determine its empirical formula. The procedure for this experiment can be found on pages 36-37 in general chemistry. Carbon copies of the data table have been attached to the back of this lab report. Mass of oxygen=mass of magnesium oxide-mass of magnesium. 0. 258g x 100 = 36. 0: % o in magnesium oxide, % mg in magnesium oxide: 0. 165g mg mass of oxygen mass of magnesium mass of magnesium oxide = mass of magnesium oxide = x x moles of o = 1: # moles mg in magnesium oxide: 24. 306g mg = 0. 00679 moles mg: # moles o in magnesium oxide. 1: mole ratio: moles of mg, theoretical yield: 0. 0058 mol o = 1. 17 ~ 1. 2:1 mgo x. 0. 274g mgo x 100 = 94. 2% your mass theoretical mass : percent yield: The purpose of this experiment was to prepare a metal oxide and determine its empirical formula.