An alpha particle, having charge +2e and mass 6.64 x 10^-27 kg,is a product of certain radioactive decays. Assume that an alphaparticle, initially very far from a gold nucleus, is fired with avelocity of 2.00 x 10^7 m/s directly toward the nucleus (charge+79e). How close does the alpha particle get to the nucleus beforeturning around? Assume that the gold nucleus remainsstationary.
I get d= 2kq1q2/mv^2
d= 2(8.98x10^9)(2)(79)/6.64x10^-27((2.00x10^7)^2)
Am I putting it in my calculator wrong? What is going on? Theanswer should be 2.74x10^-14. I get numbers in the 10^24 Wayoff!
