PH-UY 1013 Lecture 3: Motion in 1D, Constant Acceleration & Free Fall Motion
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Assume object moves in 1d and a=a o (const) at t=0. A car starts from rest and accelerates @ constant value of 2. 5m/s 2 . X(t)=0+0t+2. 5/2 t 2 =1. 25t 2 x(10) =1. 25x10 2 = 125m. Ex. suppose car travels at 40m/s when the driver slams on the brakes, causing a constant acceleration of -8m/s 2 . So were trying to answer what is t when v=0 and what is x when t =previous t value for when v=0. 2 + 2 0 xo v2 = vo a (x. Ex. suppose that in previous example a stalled car is 80m in front of a moving car when brakes are hit. What is t when x=80 and what is v when t= previous t value for when x=80. X(t)=40t-4t 2 80=40t-4t 2 20=10t-t 2 t 2 -10t+20=0 t= 2 + 2 0 xo v2 = 4 2 + 2.
