MATH 2321 Lecture 10: 2.1 pt 2

31 views2 pages

Document Summary

T i fay 27 (26) a = (fe), = (2x sply = 6. Fyx = x (d) - 2 y = (5),= (5x-3y), = 5. i fy: by (2): 2 ful, = (5x-8y)=-3. : if f is continuous, then fxy = fyx, faxxy faxy, frysy tymas i . Ex. f(x,y) = ex ny3-4x + xen (1+yz) *(fg)"=fgrg"f. : fx = evy?- 4x + e*(-4) gry=-4x) + en (itys) u= y2-4x = le-ny2_4x - zet ten (1+ y2)) fy - e* zy zip-ex + x2 1 - sex with us on. De consider a func f: ir" - r x= f(x) Let x = (x1, x2, , xn), then the vector of partial derivatives, af af of. Of icon. ax - oxz" ofn. is in the form (26 f . 24m), called the gradient vector of f, denoted if = (str. Find ff(3,4)=(2, (3, 4), of (3,4)=(x, y)) = (2x,-2)} {{6,-3)

Get access

Grade+20% off
$8 USD/m$10 USD/m
Billed $96 USD annually
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
40 Verified Answers
Class+
$8 USD/m
Billed $96 USD annually
Class+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
30 Verified Answers

Related textbook solutions

Related Documents