PHIL 130 Lecture 7: PHIL 130 - Lecture 7 (2)

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19 Jun 2018

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An out-of-control truck with a mass of 5000 kg is traveling at35.0 m/s when it starts descending a steep (15 degree) incline. Theincline is icy, so the coefficient of friction is only 0.30. Usethe work-energy theorem to determine how far the truck will skid(assuming it locks its brakes and skids the whole way) beforecoming to rest.

I don't understand the last part with Fd=K-Ki. I can't followthe variables. Which is f, k, and ki? I understand that you solvefor d. And why use Fd instead of W?

Also, in the diagram, I don't understand mgcos? and mgsin?.Why are they labeled like that and in that position? Thanks.

A 1200 kg car moving at 2.1 m/s isstruck in the rear by a 2600kg truck moving at 6.0 m/s.

calculate the initial and final kinetic energies of the system.Tocalculate the final kinetic energy you will need to find thefinalvelocity of the vehicles after the collision usingconservation ofenergy.

K_i =	2 kJ
K_f =	3 kJ

A proton with an initial speed of 800000 m/s is brought to restby an electric field.

Part A- Did the proton move into a region of higher potential orlower potential?

Part B - What was the potential difference that stopped theproton?
ÎU = ________V

Part C - What was the initial kinetic energy of the proton, inelectron volts?
K_i =_________eV

PHIL 130 Lecture 7: PHIL 130 - Lecture 7 (2)

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