MATH 095 Lecture Notes - Lecture 2: Solution Set

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30 May 2018
School
Department
Course
Math 95
Conceptual Notes
1/22/18
11:00 am 12:20 pm
Sole the euation and then ite it’s solution set.
1. X = 3 {3}
2. 2 = Y {2}
3. X 7 = 2 {9}
Addition property of Equality:
If you add the same quantity to both sides of the equation or subtract the same quantity from both side
of an equation. The euation’s solution set does not change.
Example:
X 7 = 2
X 7 + 7 = 2 + 7
X + 0 = 9
X = 9
{9}
Example:
W + 7 = -12
W + 7 7 = -12 7
W = -19
{-19}
Example:
3x 11 = 2x +15
3x 11 2x = 2x + 15 2x
X 11 = 15
X 11 + 11 = 15 + 11
X = 26
{26}
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Document Summary

Sol(cid:448)e the e(cid:395)uation and then (cid:449)(cid:396)ite it"s solution set: x = 3 {3, 2 = y {2, x 7 = 2 {9} If you add the same quantity to both sides of the equation or subtract the same quantity from both side of an equation. X 7 + 7 = 2 + 7 . W + 7 7 = -12 7 . 3x 11 2x = 2x + 15 2x . X 11 + 11 = 15 + 11 . To simplify this, i have to get rid of the parentheses. The distributive property says to multiply the outside number onto everything inside the parentheses. 16x 20 = 15x + 219 . 16x 20 + 20 = 15 x + 219 + 20 . Check: in the equation you are checking, replace x with the number you came up with and work the equation. Example: (cid:1876)(cid:889)=(cid:891)(cid:890) (cid:889)(cid:4672)(cid:1876)(cid:889)(cid:4673)=(cid:889)(cid:4666)(cid:891)(cid:890)(cid:4667) (cid:1876)=(cid:888)(cid:890)(cid:888) (cid:883)(cid:887)(cid:884)(cid:890)(cid:1877)=(cid:884)(cid:887)(cid:884)(cid:883) (cid:884)(cid:890)(cid:883)(cid:887)((cid:883)(cid:887)(cid:884)(cid:890)(cid:1877))=(cid:884)(cid:890)(cid:883)(cid:887)((cid:884)(cid:887)(cid:884)(cid:883)) (cid:884)(cid:890)(cid:883)(cid:887) (cid:883)(cid:887)(cid:884)(cid:890) (cid:1877)=(cid:884)(cid:890)(cid:883)(cid:887) (cid:884)(cid:887)(cid:884)(cid:883) (cid:1877)=(cid:884)(cid:882)(cid:891)

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