PSC 133 Lecture Notes - Lecture 5: Inelastic Collision, Elastic Collision

• School: CBU, Cal Baptist
• Department: Physical Science
• Course: PSC 133
• Professor: Suzuki

Document Summary

For the simplicity, we assume that the balls were initially on a tee and stationary (speed=0) Exit velocity is proportional to the applied force. In general, greater the applied force, the greater the exit velocity. The exit velocity and the applied force are directly proportional v = f. When applied forces are constant, greater the constant time, the greater the exit velocity. The exit velocity and the contact time are directly proportional v = ^t. When applied force and contact time are constants, greater the mass, the lesser the exit velocity. The mass and the exit velocity are "inversely" proportional v=1/m. The relationship between applied force, contact time, exit velocity and mass can be summarized in the following equation: fx^t=^(mxv) Where ^t is the tiem interval in which the force is applied. By momentum, we mean inertia in motion or, more specifically, the mass of an object multiplied by its velocity, momentum=mass x velocity.