MATH 1A Lecture Notes - Lecture 21: Indeterminate Form
Document Summary
Q: how do we find: l x 0 sinx x. Math 1a - lecture 21 - 4. 4 l"hopital"s rule. The issue is that lim x 0 sinx=0 and lim x 0 x=0 . So plugging in x=0 gives us the indeterminate form: If f ( x) and g(x) are differentiable near a , and if either: lim x a f ( x)=0=lim x a g( x) Or lim x a f ( x)= =lim x a g ( x) Then f ( x) g ( x) lim x a. =lim x a f "( x) g"( x) Take two differentiable functions zero at some point: f ( x) and g (x) such that their limits both equal. So, lim x a f ( x) g( x) =lim x a f "(a)( x a) g"(a) ( x a) lim x a f " (a) g"( a) If f ( x)= = lim x a lim x a g (x)
