CHE 1302 Lecture Notes - Lecture 21: Manganese

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20 Dec 2017
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Cl2 (in acidic solution: balance mass (here, # cl atoms on each side): Now we need to balance o and h and then balance charge using e : add h+ to mop up the o atoms and make h2o: Cl2 + 8h2o: add e to balance the charge. But 2cl atoms are reduced so 14e are needed . Mno2 (in basic solution: balance as if acidic (make sure you can do this! Mno2 + 2h2o: neutralize h+ add as many oh as there are h+, to each side: + 3e mno2 + 2h2o + 4oh : make h2o molecules: + 3e mno2 + 2h2o + 4oh : simplify: Check: mass and charge are balanced and (oxidation numbers) mn7+ + 3e mn4+ . Use the half-reaction method to balance the equation below for the reaction of manganese (iv) oxide with hydrochloric acid. Mno2(s) + hcl(aq) mncl2(aq) + cl2(g) + h2o(l)

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