MA121 Lecture 1: 备注 2019年1月22日
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So pass the one fudijohnge. tt training i go to pub fauag. igoto. The chain rule psqq. is a validargument i prpnqnqnr cpr exampley d. 11 if ni sod then e is odd then rtl is even. To prove that p. npzt. up. iq we may start with thepennies pipk and proceedto. If 4 3 15 then x 3 from thepermit 4x4325 we wish to derive heonculsiouq. pro vei. 3q. edu rite qed at the endof the proof or or 1 prove i let xez. Is even then359 is odd proof assume x is even. Then 359 31214 9 6k 10 1 k 5 1 since kez. sk 5 ez. Qed proofby example let x ez provethat if 7 9 is even then x isodd proof if x is even then 7 9 is odd. Then 7 9 7 2k 9 14k 10 1 24k 5 1 is even since kgz. tk 5 ez.
