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Physics 1402A/B Lecture Notes - Lecture 7: Magnetic Flux

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School
Western University
Department
Physics
Course
Physics 1402A/B
Professor
Jan Cami

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Document Summary

Explain the concept of magnetic flux and compute it. We can calculate the field in the solenoid using ampere"s law. If we have a very long solenoid with n = infinite number of turns, then the current through the coil is. Inside the coil whereas the field outside the coil is 0 :) Experiments have shown that changing a magnetic field causes a current. Moving a magnet near a coil induces a current in the coil. Moving a coil near a magnet also induces a current. This effect of inducing a current in something that didn"t have one before is called magnetic. To understand the concept of magnetic induction, we have to understand the concept of magnetic flux. Final studying page 1 where da is an incremental element of the surface (directed normal to the surface) and the integral is over the entire surface being considered.

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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

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Related Questions

A 300-turn solenoid with a length of 20.0 cm and a radius of 1.50 cm carries a current of 2.00 A. A second coil of four turns is wrapped tightly around this solenoid, so it can be considered to have the same radius as the solenoid. The current in the 300-turn solenoid increases steadily to 5.00 A in 0.900 s. (a) Use Ampère’s law to calculate the initial magnetic field in the middle of the 300-turn solenoid. (b) Calculate the magnetic held of the 300-turn solenoid alter 0.900 s. (c) Calculate the area of the 4-turn coil. (d) Calculate the change in the magnetic flux through the 4-turn coil during the same period. (e) Calculate the average induced emf in the 4-turn coil. Is it equal to the instantaneous induced emf? Explain. (f) Why could contributions to the magnetic field by the current in the 4-turn coil be neglected in this calculation?

A 300-turn solenoid with a length of 20.0 cm and a radius of 1.50 cm carries a current of 2.00 A. A second coil of four turns is wrapped tightly around this solenoid, so it can be considered to have the same radius as the solenoid. The current in the 300-turn solenoid increases steadily to 5.00 A in 0.900 s. (a) Use Ampere’s law to calculate the initial magnetic field in the middle of the 300-turn solenoid. (b) Calculate the magnetic field of the 300 turn solenoid after 0.900 s. (c) Calculate the area of the 4-turn coil. (d) Calculate the change in the magnetic flux through the 4-turn
coil during the same period. (e) Calculate the average induced emf in the 4-turn coil. Is it equal to the instantaneous induced emf? Explain. (f) Why could contributions to the magnetic field by the current in the 4-turn coil be neglected in this calculation?