Physics 1301A/B Lecture Notes - Lecture 5: Net Force, 2 On, Contact Force

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olivesalmon821

22 Aug 2020

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What causes motion why do things move d force dynamics of motion relationship the forces to that cause. It what is a force a push or pull. L dont have to be touching each other. Materials atoms protons tve electrons ve mass mass neutrons o charge mass mass. Z no mass no ex gravitational proton force. If any two have masses they things attract. Electric t magnetic due to charges light electric. 3 . normal force tension spring force force. 4 frictional force electromagnetic forces act between charges everything atoms charges denoted as n. Force w a contact between two force objects objects force apply on each a normal other direction to the you of the force. On what object force is applied on chain ex. F is applied chair on the by you n . Is also applied by you on the chair magnitude. 3rd law one thing apply the same cant force on thing head hitting net force.

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This experiment involves centripetal force, the force that keeps objects moving in a circular path. This force is perpendicular to the motion and directed towards the center of the circular orbit. By Newton's Second Law when a centripetal force acts on a mass (in a horizontal plane), the force continually changes the direction of the velocity without changing its magnitude, speed. This change in the direction of the velocity accounts for the centripetal acceleration of the mass, whose direction is towards the center. The relationship between the centripetal force, the mass of the orbiting object, and its speed and distance from the center is described by:

EXTENSION QUESTION: When twirling the mass, students found that despite their best efforts, they could not swing the ball so that the cord remained exactly horizontal.

(a) On the diagram of the rotating mass below, draw a force diagram of the forces acting on the mass and identify each force. Do not include any force components in this diagram.

(b) Explain why it is not possible for the ball to swing so that the cord remains exactly horizontal. Write your answer using complete sentence

greytrout41

If your car is stuck in the mud and you donât have a winch to pull it out, you can use a piece of rope and a tree to do the trick. First, you tie one end of the rope to your car and the other to a tree, then pull as hard as you can on the middle of the rope, as shown in the figure. This technique applies a force to the car much larger than the force that you can apply directly. To see why the car experiences such a large force, look at the forces acting on the center point of the rope, as shown in the figure. The sum of the forces is zero, thus the tension is much greater than the force you apply. It is this tension force that acts on the car and, with luck, pulls it free.

1.) The sum of the three forces acting on the center point of the rope is assumed to be zero because
a.) this point has a very small mass
b.) tension forces in a rope always cancel
c.) this point is not accelerating
d.) the angle of deflection is very small.

2.) when you are pulling on the rope what is the approximate direction of the tension force on the tree?
a.) north b.) south c.) east d.) west

3.) assume that you are pulling on the rope but the car is not moving. what is the approximate direction of the force of the mud on the car?
a.) north b.) south c.) east d.) west

4.) suppose your efforts work, and the car begins to move forward out of the mud. As it does so, the force of the car on the rope is
a.) zero
b.) less than the force of the rope on the car
c.) equal to the force of the rope on the car
d.) greater than the force of the rope on the car.

fuchsiadonkey795

A rectangular loop of wire has dimensions of 0.500 m by 0.300 m. The loop is pivoted at the x-axis and lies in the XY plane as shown in Figure P28.34. A uniform magnetic field of magnitude 1.50 T is directed at an angle of 40.0° with respect to the y axis with field lines parallel to the yz plane. The loop carries a current of 0.900 A in the direction shown. (Ignore gravitation.) We wish to evaluate the torque on the current loop.

(a) What is the direction of the magnetic force exerted on wire segment ab?

(b) What is the direction of the torque associated with this force about an axis through the origin?

(d) What is the direction of the torque associated with this force about an axis through the origin?

(e) Can the forces examined in parts (a) and (c) combine to cause the Loop to rotate around the x-axis?

(f) Can they affect the motion of the loop in any way? Explain.

(g) What is the direction of the magnetic force exerted on segment bc?

(h) What is the direction of the torque associated with this force about an axis through the origin?

(i) What is the torque on segment ad about an axis through magnetic force exerted on segment bc? (h) What is the direction of the torque associated with this force about an axis through the origin? (i) What is the torque on segment ad about an axis through the origin? O) From the point of view of Figure P28.34, once the loop is released from rest at the position shown, will it rotate clockwise or counterclockwise around the x-axis? (k) Compute the magnitude of the magnetic moment of the loop. (1) What is the angle between the magnetic moment vector and the magnetic field? (m) Compute the torque on the loop using the results to parts (k) and (1).

scarletbeetle53

Physics 1301A/B Lecture Notes - Lecture 5: Net Force, 2 On, Contact Force

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