Philosophy 1305F/G Lecture 4: Philosophy 1305F/G - Lecture 4.docx

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25 Apr 2012

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Revisiting st. thomas aquinas" second argument (a posteriori cosmological) Either the chain that produced frank was: infinite or finite major premise: not infinite minor premise, therefore, finite conclusion. If so, therefore there is a first cause which is an uncaused cause, which is what we mean by god. The exhaustive conclusion is that it cannot be infinite and finite this is impossible. If the beginning of everything is infinite, then the future too must be infinite. If this is true, then frank could never come to exist. If all the causes that preceded frank, frank could never exist, because there is no beginning, middle, or end. With infinity we don"t have a first, without a first we don"t have a middle, and without a middle, there is no present/end. The present is currently the end because it is what we experience now; it is the end of the line of progression that has led to frank.

Related Questions

Why is Gravitational Energy negative?

My understanding was:
A zero point is arbitrary because only change in potential energyis of use.
As gravity approaches zero over infinite distance. We say gravityis zero at a distance of infinity.
Therefore as an object approaches a centre of gravity, it gainskinetic energy which comes from a potential energy; making itnegative?

But i am confused; at the gravitational centre shouldn't gravity bezero?

Two hypothetical planets of masses m1 and m2 and radii r1 and r2, respectively, are nearly at rest when they are an infinite distance apart. Because of their gravitational attraction, they head each other a collision course. When their centre to centre separation is d, find an expression for the speed of each planet and for their relative speed.

salmonhare521

For a finite continuous charged object we can use integration tofind the electric potential at a point. As is the case for anyfinite charge distribution, the value of the electric potential canbe chosen to be zero at any reference point which is sufficientlyfar from the distribution. I.e. One can (and usually does) chooseV_(infinity) = 0 at r = infinity.

Consider a rod of length L extending from the origin along thepositive x axis, and a point P located at x = -D, which is adistance D from the origin. The task is to find the electricpotential (voltage) at the point P.

ChargedRod

The above Figure shows the rod. Highlighted is one small piece ofthe rod which is located at a position x and has length (dx). Note:In answers below, if you want to include dx, it is good practice toput (dx) in parentheses.

(a) Suppose that the rod is uniformly charged to a value Q. Writethe expression for the linear charge density, using the symbolsalready defined.
lambda = 1Click here to preview your answer.

(b) The small piece of the rod has length dx. In terms of symbolsL, x, (dx), D, Q and constants, what is the infinitesimal charge onthe rod? You may need to enclose dx in parentheses for it todisplay properly.
dq = 2Click here to preview your answer.

c) What is the distance from the point to the small piece of therod? Answer in terms of symbols x, L, D, (dx) and constants.
3Click here to preview your answer.

(d) What is the infinitesimal voltage produced at point P from thisdq? Answer in terms of symbols k, Q, x, L, D, (dx) andconstants.
dV = 4Click here to preview your answer.

(e) The final step would be to integrate this result. What are thelower 5Click here to preview your answer.
and upper 6Click here to preview your answer. limits on theintegration? Answer in terms of symbols x, L, D, (dx) andconstants.

Note that if the charge of the rod had not been uniform, we wouldneed to know lambda as a function of x and use that in place of(Q/L).

Philosophy 1305F/G Lecture 4: Philosophy 1305F/G - Lecture 4.docx

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