Kinesiology 2241A/B Lecture Notes - Lecture 12: Density Of Air, Personal Flotation Device, Buoyancy
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21 Oct 2018
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Looking at centre of gravity for the whole body. Have person lying in the table and the table is only contacting the ground at 2 points: at feet and head. Getting information from physically measuring and then solving for an unknown. 2 points at which this system can pivot: where it contacts the ground at the scale and below feet. Have to assign a point where this whole thing pivots around an axis. Net torque on this has to be zero because its static (anything not moving, sum of all torques has to be zero) At the scale is point where its being held up. Have 2 torques apply that are zero therefore the system isn"t moving. T= f x fa + f x fa. Spinning the system clockwise so it(cid:1685)s a negative torque. Force of weight x the force arm which is d in this diagram.