Engineering Science 1036A/B Lecture 9: AM 1413 (2019-2020) – Section 001

• School: Western University
• Department: Engineering Science
• Course: Engineering Science 1036A/B
• Professor: Quazi Rahman

Document Summary

Volumes - solids of revolution (section 7. 1) Solution. x 2 + 3 = x 2 +(cid:0) 3(cid:1)2. Then, dx = 3 sec2 d . x x 2 + 3. So, px 2 + 3 = 3 sec , cot = 1 cos sin cos d . Rewrite the denominator as dx (4x 2 25)3/2 = (4x 2 25) 4x 2 25. So it contains a term x 2 a2, where a = 5. 2 then dx = sec , sec tan d . 2(cid:17)2 x sin = qx 2 (cid:0) 5. 2 sec tan d tan2 . 50z cos sin2 d d = cos sin2 cos2 d . 50z du (4x 2 25)3/2 = u2 = Techniques of integration (cond) dx (a > 0). Then, dx = a sec tan d and x 2 a2 = a tan . = ln| sec + tan | + c1 = ln x. = ln x + x 2 a2.